Number System - gkquestionsguru.com

Number System

41. In a two-digit positive number, the unit digit is equal to the square of ten’s digit. The difference between the number formed by interchanging the digits and the original number is 54. What is 40% of the original number
दो अंकों की धनात्मक संख्या में, इकाई अंक दहाई अंक के वर्ग के बराबर है। अंकों को आपस में परिवर्तित करने से प्राप्त संख्या और वास्तविक संख्या के मध्य अंतर 54 है। वास्तविक संख्या का 40% कितना है?1. 9.6
2. 73
3. 15.6
4. None of these[bg_collapse view=”button-orange” color=”#4a4949″ expand_text=”View Answer” collapse_text=”Hide Answer”]Option “3” is correct.

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42.
1.
2.
3.
4. [bg_collapse view=”button-orange” color=”#4a4949″ expand_text=”View Answer” collapse_text=”Hide Answer”]Option “4” is correct.
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43.
1. 1/4
2. 1/16
3. 1/32
4. 1/64[bg_collapse view=”button-orange” color=”#4a4949″ expand_text=”View Answer” collapse_text=”Hide Answer”]Option “3” is correct.
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44.
1. 2
2. 4
3. 6
4. 1[bg_collapse view=”button-orange” color=”#4a4949″ expand_text=”View Answer” collapse_text=”Hide Answer”]Option “4” is correct.[/bg_collapse]
45.
1. 1
2. 3
3. 6
4. 12[bg_collapse view=”button-orange” color=”#4a4949″ expand_text=”View Answer” collapse_text=”Hide Answer”]Option “2” is correct.
The value of x should be such that the left hand side after completely removing the square root signs should be an integer. For this to happen, first of all the square root of 3x should be an integer. Only 3 and 12 from the options satisfy this requirement. If we try to put x as 12, we get the square root of 3x as 6.Then the next point at which we need to remove the square root sign would be 12 + 2(6) = 24 whose square root would be an irrational number. This leaves us with only 1 possible value (x = 3). Checking for this value of x we can see that the expression is satisfied as LHS = RHS.[/bg_collapse]
46.
1. 2
2. 4
3. 0
4. 1[bg_collapse view=”button-orange” color=”#4a4949″ expand_text=”View Answer” collapse_text=”Hide Answer”]Option “1” is correct.
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47. Let N be the least number of 6 digits, which when divided by 4, 6, 10 and 15 leaves the remainder 2 in each case. Find the sum of digits in N
मानाकि N, 6 अंकों की न्यूनतम संख्या है, जिसे जब 4, 6, 10 और 15 द्वारा विभाजित किया जाता है तो प्रत्येक दशा में 2 शेष बचता है। N के अंकों का योग ज्ञात कीजिये।1. 3
2. 5
3. 4
4. 6[bg_collapse view=”button-orange” color=”#4a4949″ expand_text=”View Answer” collapse_text=”Hide Answer”]Option “2” is correct.
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48. To what power – 3 showed be raised to get – 19683?
– 3 पर कितनी घात लगानी चाहिए ताकि – 19683 प्राप्त हो?1. 7
2. 9
3. -7
4. -9[bg_collapse view=”button-orange” color=”#4a4949″ expand_text=”View Answer” collapse_text=”Hide Answer”]Option “2” is correct.
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49.
1. 7
2. 9
3. -7
4. -9[bg_collapse view=”button-orange” color=”#4a4949″ expand_text=”View Answer” collapse_text=”Hide Answer”]Option “2” is correct.
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50.
1. 1
2. 0
3. 119
4. 120[bg_collapse view=”button-orange” color=”#4a4949″ expand_text=”View Answer” collapse_text=”Hide Answer”]Option “1” is correct.
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