111. If increasing 20 by P percentage gives the same result as decreasing 60 by P percentage, what is P percentage of 70?

यदि 20 में P प्रतिशत की वृद्धि करने से समान परिणाम मिलता है जो 60 में P प्रतिशत घटाने से, तो 70 का P प्रतिशत कितना है?

Option “D” is correct.

Given,

Increasing 20 by P% gives the same result as decreasing 60 by P%

Concept:

If a number increase by x%, then increased number = Actual number × (100 + x)/100

If a number decrease by x%, then decreased number = Actual number × (100 – x)/100

Calculation:

According to the question

20 × (100 + P)/100 = 60 × (100 – P)/100

⇒ 2000 + 20P = 6000 – 60P

⇒ 60P + 20P = 6000 – 2000

⇒ 80P = 4000

⇒ P = 4000/80

⇒ P = 50

∴ P% of 70 = 70 × (50/100) = 35

112. A and B got an equal number of votes. 5% of the votes which B got were disqualified later. A won the election by 14925 votes. Find the total votes which were qualified.

A और B को बराबर मत प्राप्त हुए हैं। B के 5% मत बाद में अयोग्य घोषित कर दिए गए थे। A ने 14925 मतों से चुनाव जीत लिया है। कुल योग्य मतों की संख्या ज्ञात कीजिए।

Option “A” is correct.

Given: A and B got an equal number of votes. 5% of the votes B got were disqualified later. A won the election by 14925 votes.

Formula: If A got a% votes and B got b% votes, difference in the votes = (a – b) % of Total votes

Calculation:

Let the total votes be 100%

A = B = 50%

5% of the votes of B were disqualified

5% of 50% = 2.5%

So, A = 50% and B = 47.5%

⇒ 50% – 47.5% = 14925

⇒ 2.5% = 14925

⇒ 1% = 5970

⇒ 100 – 2.5 = 97.5% votes qualified

⇒ 97.5% = 97.5 × 5970

⇒ 582,075

113. Ram spends 75% of his income and he is able to save 1,500 per month, Find Ram’s annual income:

 राम अपनी आय का 75% खर्च करके प्रति माह 1,500 बचत करता है। राम की वार्षिक आय ज्ञात कीजिए। 

Option “D” is correct.

Given

Ram’s monthly saving = 1,500

Ram’s expenditure = 75% of income

Concept = Total income — Expenditure = Saving

Calculation:

Let Ram income = 100

Ram’s expenditure = 75% of 100 ⇒ 75

∴ Ram’s saving = 100 — 75 ⇒ 25

∴ Ram’s monthly income = (1,500/25) × 100

= 6,000

Ram’s annual income = 6,000 × 12

= 72,000

114. Fresh fruit contains 65% water and dry fruit contains 25% water, then how much dry fruits can be obtained from 300 kg of fresh fruits(in kg)?

ताजे फल में 65% पानी होता है और सूखे मेवे में 25% पानी होता है, फिर 300 किलोग्राम ताजे फलों से कितने सूखे मेवे प्राप्त किए जा सकते है?

Option “C” is correct.

Calculations:

If 65% water then 35% fresh fruits

and 25% water then 75% dry fruits

now,

Fresh fruits × 35% = Dry fruits × 75%

⇒ 300 × 35 = Dry fruits × 75 (∵ Fresh fruits = 300 kg)

⇒ 12 × 35 = Dry fruits× 3

∴ Dry fruits = 140 kg

115. In an exam, Rahul scored 440 marks and David scored 68% marks. If Rahul scored 20% more than that of David, then find the maximum marks in the exam?

एक परीक्षा में, राहुल ने 440 अंक प्राप्त किए और डेविड ने 68% अंक प्राप्त किए। यदि राहुल ने डेविड से 20% अधिक अंक प्राप्त किए, तो परीक्षा में अधिकतम अंक ज्ञात कीजिए?

Option “B” is correct.

The maximum marks in the exam = x

x * (68 + 20)% = 440

x * 88/100 = 440

x = 440 * 100/88

x = 500

116. The total population of a city is 2880 and the ratio of the number of females in the city is 20% less than that of males. If the number of illiterate males in the city is 400, then find the number of literate males in the city?

एक शहर की कुल जनसंख्या 2880 है और शहर में महिलाओं की संख्या का अनुपात पुरुषों की तुलना में 20% कम है। यदि शहर में निरक्षर पुरुषों की संख्या 400 है, तो शहर में साक्षर पुरुषों की संख्या ज्ञात कीजिये?

Option “C” is correct.

Let the total number of males in the city = 5x

And the total number of females in the city = 5x * 80/100 = 4x

The total number of males in the city = 2880 * 5x/ (5x + 4x) = 1600

The total number of literate males in the city = 1600 – 400 = 1200

117. A spends 20% of his salary on food. Out of the remaining salary, A spends 60% on rent and entertainment and he invests remaining salary in stock market. If the sum of the amount invested in stock market and amount spend on food is Rs.2600, then find the salary of A.

A अपने वेतन का 20% भोजन पर खर्च करता है। शेष वेतन में से, A, किराए और मनोरंजन पर 60% खर्च करता है और वह शेष वेतन शेयर बाजार में निवेश करता है। यदि शेयर बाजार में निवेश की गई राशि और भोजन पर खर्च की गई राशि का योग 2600 रुपये है, तो A का वेतन ज्ञात कीजिए।

Option “C” is correct.

Total salary = 100x

Amount spend on food = 20x

Remaining salary = 100x – 20x = 80x

Amount spend on rent and entertainment = 80x * 60/100 = 48x

Amount invested in stock market = 32x

32x +20x = 2600

52x = 2600

x = 50

Total salary of A = 50 * 100 = Rs.5000

118. The total number of students in school B is 20% less than that of school A and the ratio of the number of boys and girls in school A is 3:2. If the average number of boys and girls in school B is 160, then find the number of boys in school A is what percentage of the total number of students in school B?

स्कूल B में छात्रों की कुल संख्या स्कूल A से 20% कम है और स्कूल A में लड़कों और लड़कियों की संख्या का अनुपात 3:2 है। यदि स्कूल B में लड़कों और लड़कियों की औसत संख्या 160 है, तो स्कूल A में लड़कों की संख्या स्कूल B में छात्रों की कुल संख्या का कितना प्रतिशत है?

Option “A” is correct.

The total number of students in school B = 160 * 2 =320

And the total number of students in school A = 320 * 100/80 = 400

The number of boys in school A = 400 * 3/(3+2) = 240

Required percentage = 240/320 * 100= 75%

Shortcut method:

The total number of students in school B = 4x

And the total number of students in school A = 4x*100/80=5x

The number of boys in school A = 5x * 3/(3+2) = 3x

Required percentage = 3x/4x*100 = 75%

119. If the price of rice is reduced by 20% and the consumer increased his consumption by 8 kg, so that the total expenditure remains the same, then find the initial consumption of the rice?

यदि चावल की कीमत 20% कम हो जाती है और उपभोक्ता अपनी खपत में 8 किग्रा की वृद्धि करता है, ताकि कुल व्यय समान रहे, तो चावल की प्रारंभिक खपत ज्ञात कीजिये?

Option “C” is correct.

Let the price of rice per kg = a

And the initial consumption of rice = b

a*b = a * 80/100 * (b+8)

b = 4b/5 + 32/5

b = 32 * 5/5

b = 32 kg

120. Out of a certain number of students in a class, 20% of students likes only Maths and 30% of students likes only science and 15% of students who do not like both the subjects and the remaining students likes both subjects. If 21 students who like both subjects, then find the number of students who like Only Maths.

एक कक्षा में छात्रों की एक निश्चित संख्या में से, 20% छात्र केवल गणित पसंद करते हैं और 30% छात्र केवल विज्ञान पसंद करते हैं और 15% छात्र जो दोनों विषयों को पसंद नहीं करते हैं और शेष छात्रों को दोनों विषय पसंद हैं। यदि 21 छात्र दोनों विषयों को पसंद करते हैं, तो केवल गणित पसंद करने वाले छात्रों की संख्या ज्ञात कीजिए ।

Option “C” is correct.

Total number of students in the class = 100x

Number of students who likes Only Maths = 20x

Number of students who likes Only Science = 30x

Number of students who do not like both subjects = 15x

Number of students who likes both subjects = 100x – (20x + 30x + 15x) = 35x

35x = 21

x = 21/35 = 3/5

Number of students who likes Only Maths = 20 * 3/5 = 12

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