271. 24 % of monthly salary of P is equal to 32% of monthly salary of Q and 16 % of monthly salary of Q is equal to 20 % of monthly salary of R. If the monthly income of R is Rs. 48000, then find the difference between the income of P to that of Q?

P के मासिक वेतन का 24%, Q के मासिक वेतन के 32% के बराबर है और Q के मासिक वेतन का 16%, R के मासिक वेतन के 20% के बराबर है। यदि R की मासिक आय 48000 रु है, तो P की आय से Q के बीच का अंतर ज्ञात कीजिए ?

A. Rs. 15000
B. Rs. 20000
C. Rs. 18000
D. Rs. 24000
E. None of these

Option “B” is correct.

 (24/100)*P = (32/100)*Q

P/Q = (32/24) = 4/3

(16/100)*Q = (20/100)*R

Q/R = 20/16 = 5/4

P : Q : R = 20 : 15 : 12

The monthly income of R = Rs. 48000

12’s = 48000

1’s = 4000

Required difference = 5’s = Rs. 20000

272. A fruit seller had some oranges and apples. He sold 20% oranges to A, 40% of remaining to B and had 48 oranges left. Similarly, he sold 40% apples to A, 100 apples to B and had 10% apples left. Find the total number of apples and oranges that the shopkeeper had initially.

एक फल विक्रेता के पास कुछ संतरे और सेब थे। उसने A को 20% संतरे , शेष का 40%, B को बेचा और उसके पास 48 संतरे शेष थे। इसी तरह, उसने A को 40% सेब बेचे, B को 100 सेब और 10% सेब शेष रहे। प्रारंम्भ में दुकानदार के पास सेब और संतरों की कुल संख्या को ज्ञात कीजिये।

A. 200
B. 250
C. 300
D. 350
E. 400

Option “C” is correct.

Let ‘a’ and ‘b’ are number of oranges and apples respectively.

Oranges sold to A = 20/100 * a = 0.2 a

Oranges sold to B = (a – 0.2a) * 40/100 = 0.32 a

Remaining number of oranges = a – (0.2a + 0.32 a) = 0.48 a

=> 48 = 0.48 a

=> 100 = a

Apples sold to A = 40/100 * b = 0.4 b

Remaining number of Apples = 10/100 * b =0.1 b

Apples sold to B = 100

=> 100 = b – (0.4 b + 0.1 b)

=> 100 = 0.5 b

=> 200 = b

Total number of apples and oranges = a + b = 100 + 200 = 300

273. Find the average increase rate (per annum)if the population in the first year is increased by 30%, second year is increased by 10% and that in the third yearis decreased by 10%.

औसत वृद्धि दर (प्रति वर्ष) ज्ञात करें यदि पहले वर्ष में जनसंख्या में 30% की वृद्धि हुई है, तो दूसरे वर्ष में 10% की वृद्धि हुई है और तीसरे वर्ष में 10% की कमी हुई है।

A. 8.64
B. 9
C. 9.57
D. 9.52
E. 4

Option “C” is correct.

Let the total population in the city = 100x

Increase after 3 years = 100x * 130/100 * 110/100 * 90/100= 128.7x

Required average = (100 – 128.7)/3 = 28.7/3 = 9.57

274. During dieting, every month the weight of Suku was decreased by 10% of the previous month. In April he started dieting and in July of the same year, his weight was 87.48 kg. What was his weight when he started dieting?

डाइटिंग के दौरान, हर महीने सुकु का वजन पिछले महीने के मुकाबले 10% कम हो गया था। अप्रैल में उन्होंने डाइटिंग शुरू की और उसी साल जुलाई में उनका वजन 87.48 किलोग्राम था। जब उन्होंने डाइटिंग शुरू की तो उनका वजन कितना था?

A. 120 kg
B. 124 kg
C. 116 kg
D. 110 kg
E. None of the above

Option “A” is correct.

In April, let his weight = a kg

In May, his weight = 90% of a = 0.9a kg

In June, his weight = 90% of 0.9a = 0.81a kg

In July, his weight = 90% of 0.81a = 0.729a = 87.48 kg

a = 87.48/0.729 = 120 kg

Or

In April his weight = 87.48 * 100/90 * 100/90 * 100/90 = 120 kg

275. A, B and C went for dinner in a restaurant. A’s meal costs 40% more than that of B while the cost of the meal of A was 2/3 of the meal of C. If B paid Rs. 200 for his meal then find the average expenses of the three persons?

A, B और C एक रेस्तरां में रात के खाने के लिए गए। A के भोजन की लागत B की तुलना में 40% अधिक है, जबकि A के भोजन की लागत C के भोजन की 2/3 थी। यदि B ने उसके भोजन के लिए 200 रु का भुगतान किया, तो तीनों व्यक्तियों का औसत व्यय ज्ञात करें?

A. 340
B. 420
C. 280
D. 300
E. None of these

Option “D” is correct.

Bill paid by B= Rs. 200

Bill paid by A= 200*(140/100) = Rs. 280

(2/3) of C = 280

C = 280*(3/2)

C = Rs. 420

Total bill paid by them = 200 + 280 + 420 = Rs. 900

Average expenses = 900/3 = Rs. 300

276. Manoj scored 360 marks in an exam and Sanjay got 76 % marks in the same exam which is 20 marks more than Manoj. If the minimum passing marks in the exam is 50 %, then how much more marks did Manoj score than the minimum passing marks?

मनोज ने एक परीक्षा में 360 अंक प्राप्त किए और संजय ने उसी परीक्षा में 76% अंक प्राप्त किए जो कि मनोज से 20 अंक अधिक है। यदि परीक्षा में न्यूनतम उत्तीर्ण अंक 50% हैं, तो मनोज ने न्यूनतम उत्तीर्ण अंकों की तुलना में कितने अधिक अंक प्राप्त किए हैं?

A. 130 marks
B. 150 marks
C. 110 marks
D. 175 marks
E. None of these

Option “C” is correct.

Manoj’s score = 360 marks, Sanjay = 76 % = Manoj’s score + 20

Sanjay = 360 + 20 = 380 = 76 % of total marks

(76/100)*x = 380

x = 380*(100/76) = 500

Minimum passing marks = 50 % of total marks

= > (50/100)*500 = 250

Manoj scored 110 marks more than the passing marks.

277. The income of Gokila is 25% less than that of Shri and the expenditure of Gokila is 12.5% more than that of Shri. If the savings of Shri and Gokila is Rs.6000 and Rs.3000 respectively, then find the expenditure of Gokila.

गोकिला की आय श्री से 25% कम है और गोकिला का व्यय श्री की तुलना में 12.5% अधिक है। यदि श्री और गोकिला की बचत क्रमशः 6000 रुपये और 3000 रुपये है, तो गोकिला का व्यय ज्ञात कीजिए।

A. Rs.4500
B. Rs.6300
C. Rs.5400
D. Rs.3600
E. None of these

Option “A” is correct.

The ratio of the income of Gokila to Shri = 75 : 100 = 3 : 4

The ratio of the expenditure of Gokila to Shri = 112.5 : 100 = 9 : 8

3x – 9y = 3000 —(1)

4x – 8y = 6000 —(2)

From (1) and (2),

12x – 36y = 12000

– 12x + 24y = – 18000

12y = 6000

y = 500

The expenditure of Gokila = 9 * 500 = Rs.4500

278. The amount divided into two parts. If 70% of the first part is Rs.400 more than the half of the second part and 90% of the second part is Rs.1120 more than 80% of first part, then find the amount?

राशि को दो हिस्सों में विभाजित किया गया। यदि पहले हिस्से का 70% भाग, दूसरे हिस्से के आधे भाग से 400 रु अधिक है और दूसरे हिस्से का 90% भाग, पहले हिस्से के 80% भाग से 1120 रु अधिक है, तो राशि को ज्ञात कीजिए?

A. Rs.8000
B. Rs.7800
C. Rs.6600
D. Rs.8800
E. Cannot be determine

Option “D” is correct.

Amount = a

First part = x

Second part = a – x

70/100 x – (a – x) * 50/100 = 400

70x – 50a + 50x = 40000

12x – 5a = 4000———(1)

90/100 * (a – x) – 80x/100 = 1120

90a – 90x – 80x = 112000

9a – 17x = 11200 ———(2)

(2) * 5 + (1) * 9

23x = 92000

x = Rs.4000

12 * 4000 – 4000 = 5a

Rs.8800 = a

279. Kamal had Rs. 5575 in his bank account two years ago. In the first year, he deposited 28% of the amount in his bank account. In the second year, he deposited 40% of one year ago in his bank account. Find the 55% of the amount of Kamal at present in his bank account?

कमल के पास दो साल पहले उनके बैंक खाते में 5575 रुपये थे पहले वर्ष में, उन्होंने अपने बैंक खाते में 28% मात्रा जमा की। दूसरे वर्ष में, उसने एक साल पहले के जामा मात्रा का 40% अपने बैंक खाते में जमा किया। वर्तमान में उसके बैंक खाते में मात्रा का 55% ज्ञात करें?

A. Rs. 6284.6
B. Rs. 4992.8
C. Rs. 3856.2
D. Rs. 5072.5
E. None of these

Option “E” is correct.

Two years ago amount in Kamal bank account = Rs. 5575

In the first year amount will be = 5575 × 128/100 = Rs. 7136

In the second year amount will be = 7136 × 140/100 = Rs. 9990.4

So, the amount at present with Kamal is = 9990.4 × 55/100 = Rs. 5494.72

280. In an office, there is a certain number of employees, 20% of the employees do not like sweets, 62.5% of employees who like sweets are females and the average number of male and female employees who does not like sweet is 95. Then find the number of male employees who like sweets?

एक कार्यालय में कर्मचारियों की एक निश्चित संख्या है, 20% कर्मचारियों को मिठाई पसंद नहीं है, 62.5% कर्मचारी जो मिठाई पसंद करते हैं वे महिलाएं हैं और पुरुष और महिला कर्मचारियों की औसत संख्या जो मिठाई पसंद नहीं करते हैं, 95 है। तो मिठाई पसंद करने वाले पुरुष कर्मचारियों की संख्या ज्ञात कीजिये?

A. 285
B. 260
C. 245
D. 250
E. None of these

Option “A” is correct.

Let, the number of employees in the office =100X

The number of male and females employees who does not like sweets=95*2=190

The number of employees in office=190*100/20=950

The number of employees who like sweets=950*80/100=760

The number of males who like sweets=760*3/8=285

 

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