61. Manish’s salary is half of Ravi’s salary. Ravi’s salary is how much percentage more than Manish’s Salary?

मनीष का वेतन, रवि के वेतन का आधा है। रवि का वेतन, मनीष के वेतन से कितने प्रतिशत अधिक है?

Option “A” is correct.

Let salary of Ravi be Rs. 100

Salary of Manish = 100 × (1/2) = Rs. 50

Ravi salary is more than that of Manish by = 100 – 50 = 50

Ravi salary is more than that of Manish by (in%) = (50/50) × 100 = 100%

62. A person saves his income by 20%. If, his income increases by 25% while his savings remains same, then find percentage increase in his expenditure.

एक व्यक्ति अपनी आय का 20% बचाता है। यदि, उसकी आय में 25% की वृद्धि होती है, जबकि उसकी बचत समान रहती है, तो उसके व्यय में प्रतिशत वृद्धि ज्ञात करें।

Option “D” is correct.

Let, income be 100x

Then, savings = 100x × 20% = 20x

Hence, Expenditure = 100x – 20x = 80x

Now, new income = 100x × 125% = 125x

Hence, new expenditure = 125x – 20x = 105x

∴ Required percentage = [(105x – 80x)/80x] × 100 = 31.25%

63. 25 litres of a mixture contains 30% of spirit and the rest is water. If 5 litres of water is mixed in it, the percentage of spirit in the new mixture is:

25 लीटर में मिश्रण में 30% स्प्रिट और शेष पानी है। यदि इसमें 5 लीटर पानी मिलाया जाता है तो नए मिश्रण में स्प्रिट का प्रतिशत है:

Option “D” is correct.

Given:

Total quantity of mixture = 25 

Percentage of spirit = 30%

Calculations:

Quantity of sprit in 25 liters mixture = 25 × 30/100 = 7.5

New quantity of mixture if 5 liters water add = 25 + 5 = 30

New percentage of spirit in new mixture = (7.5/30) × 100 = 25%

∴ New percentage of spirit in new mixture is 25% 

64. 50% of a = b, then b% of 40 is the same as _________ times of a.

a का 50% = b है, तो 40 का b%, a के _________ गुना के बराबर है।

Option “D” is correct.

50%of a = b

⇒ 50/100 × a = b
⇒ a/b = 100/50

⇒ a = 2b      —- (1)
Now, b/100 × 40 = x × a

⇒ b/100 × 40 = x × 2b

⇒ x = 0.2

65. If x and y are two positive numbers and x is 25% greater than y, what is the value of the ratio y/x?

यदि x और y दो धनात्मक संख्याएँ हैं और x, y से 25% अधिक है, तो y/x अनुपात का मान क्या है?


Option “B” is correct.

Let the y be 100

⇒ x = 100 × 125/100 = 125

∴ Ratio of y/x = 100/125 = 0.80

66. Sandy donated 13% of her salary to an organization working for the blind people, 12% of her salary to the orphanage, 14% of her salary, the institution working for the physically challenged people, and 16% of her salary The institution helping the medical aid. The remaining amount of salary Rs 24345 is deposited in the bank for monthly expenditure. Find out the amount donated in the orphanage

सैंडी अपने वेतन का 13% नेत्रहीन व्यक्तियों के लिए काम करने वाले एक संगठन को, वेतन का 12% अनाथालय को, वेतन का 14% शारीरिक रूप से अक्षम व्यक्तियों के लिए कार्य करने वाले संगठन और अपने वेतन का 16% चिकित्सकीय सहायता प्रदान करने वाली एक संस्था को प्रदान करती है। वेतन की शेष राशि 24345 रुपए को मासिक खर्च के लिए बैंक में जमा किया जाता है। तो अनाथालय में दी गयी राशि ज्ञात कीजिए। 

Option “D” is correct.

Let the total salary of the Sandy be Rs. x

Total Percentage of donated salaries = 13 + 12 + 14 + 16 = 55%

According to the question

x × 45/100 = 24345

⇒ x = 24345 × 100/45 = 54100

∴ The amount donated in the orphanage = 54100 × 12/100 = 6492

67. If X is 80% more than Y, then Y is how much percentage less than X?

यदि X, Y से 80% अधिक है, तो Y, X से कितने प्रतिशत कम है?

Calculation:

According to question, X is 80% more than Y

⇒ X = (100 + 80)/100 Y

⇒ X/Y = 180/100

⇒ X/Y = 9/5

Hence, the ratio of X : Y = 9 : 5

∴ Required percentage = (4/9) × 100 = 44.44% 

68. The present population of a village is 28000. If it increases at the rate of 5% per annum, population after 2 years will be:

एक गाँव की वर्तमान जनसंख्या 28000 है। यदि इसमें 5% प्रति वर्ष की दर से वृद्धि होती है, तो 2 वर्ष के बाद जनसंख्या कितनी होगी?

Option “C” is correct.

Given:

Present population of village = 28000

Rate at which population increases = 5%

Time period = 2 years

Formula used:

Pn=P(1+R100)nPn=P(1+R100)n

Where, Pn = Population after n years

P = Present population

R = Rate of growth of population

n = time period (in years)

Calculations:

Population after 2 years,

P2=28000(1+5/100)2

P2=28000(21/20)2

P2=28000(441/400)

⇒ P2 = 70 × 441

⇒ P2 = 30870

∴ The population after 2 years will be 30870

69. There are 30% monkeys, 40% deer, 10% wolves and 20% lions in a forest. If all 100 deer are captured from the forest, how many lions are there in the forest?

एक जंगल में 30% बंदर, 40% हिरण, 10% भेड़िये और 20% शेर हैं। यदि जंगल से सभी 100 हिरण को पकड़ लिया जाता है, तो अब जंगल में कितने शेर हैं?

Option “A” is correct.

Given:

Monkey = 30% of total number of animals

Deer = 40% of total number of animals

Wolves = 10% of total number of animals

Lions = 20% of total number of animals

Total number of deer in a forest = 100

Calculation:

Let the total number of animals in a forest be x.

Total number of deer in a forest = 100

Percentage of deer in a forest = 40% of total number of animals

According to the question,

Total number of deer in a forest = Percentage of deer in a forest

⇒ 100 = 40% of x

⇒ 100 = 40 × x/100

⇒ x = 100 × 100/40

⇒ x = 250

Total number of lions = 20% of total number of animals

⇒ 20% × 250

⇒ 20 × 250/100

⇒ 50

∴ total number of lions in a forest are 50.

70. The total number of boys in a college is 16% more than the total number of girls in a college. What is the ratio of the total number of boys compared to girls in that college?

एक कॉलेज में लड़कों की कुल संख्या कॉलेज में लड़कियों की कुल संख्या से 16% अधिक है। उस कॉलेज में लड़कियों की तुलना में लड़कों की कुल संख्या का अनुपात क्या है?

Option “B” is correct.

Given:

Total number of boys in a college = 116% of the total number of girls in a college

Calculations:

Let the total number of girls in a college be 100

Total number of boys = (116/100) × 100

⇒ 116

Ratio of total number of boys to girls = 116/100

⇒ 29 ∶ 25

∴ The ratio of the total number of boys compared to girls in that college is 29 ∶ 25

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