Directions:(1-5) Find the wrong term in the series given below.

1. 413, 425, 465, 585, 787, 1065

Ans:4
The next term is obtained by adding the number to the product of its digits.

413 + 12 = 425

425 + 40 = 465

465 + 120 = 585

585 + 200 = 785

785 + 280 = 1065

 

2. 40, 60.0, 92.0, 135.0, 202.5, 303.75

Ans:4
The pattern is as follows:

40 x 1.5 = 60.0

60.0 x 1.5 = 90.0

90.0 x 1.5 = 135.0

135.0 x 1.5 = 202.5

202.5 x 1.5 = 303.75

 

3. 63, 593, 994, 1284, 1483, 1603

Ans:5
The pattern is as follows:

63 + 232 + 1 = 593

593 + 202 + 1 = 994

994 + 172 + 1 = 1284

1284 + 142 + 1 = 1481

1481 + 112 + 1 = 1603

 

4. 120, 136, 130, 132, 130, 131

Ans:4
From the 3rd number, each successive term is average of previous 2 terms:

(120 + 136)/2 = 128

(136 + 128)/2 = 132

(128 + 132)/2 = 130

(132 + 130)/2 = 131

 

5. 332, 336, 374, 376, 412, 416

Ans:3
The next term is obtained by adding the number to the square of the last digit of the previous number.

332 + 22 = 336

336 + 62 = 372

372 + 22 = 376

376 + 62 = 412

412 + 22 = 416

 

Directions:(6-10) Find the next term in the series.

6. 538, 658, 898, 1474, 1586, ?

Ans:3
The next term is obtained by adding the number to the product of its digits.

538 + 5 x 3 x 8 = 658

658 + 6 x 5 x 8 = 898

898 + 8 x 9 x 8 = 1474

1474 + 1 x 4 x 7 x 4 = 1586

1586 + 1 x 5 x 8 x 6 = 1826

 

7. 15, 49, 201, 1011, 6073, ?

Ans:2
The pattern is as follows:

(15 x 3) + 4 = 49

(49 x 4) + 5 = 201

(201 x 5) + 6 = 1011

(1011 x 6) + 7 = 6073

(6073 x 7) + 8 = 42519

 

8. 26, 22, 36, 92, 336, ?

Ans:3
The pattern is as follows:

(26 x 1) – 4 = 22

(22 x 2) – 8 = 36

(36 x 3) – 16 = 92

(92 x 4) – 32 = 336

(336 x 5) – 64 = 1616

 

9. 341, 559, 855, 1241, 1729, ?

Ans:1
The pattern is as follows:

53 + 63 = 341

63 + 73 = 559

73 + 83 = 855

83 + 93 = 1241

93 + 103 = 1729

103 + 113 = 2331

 

10. 29, 31, 36, 47, 64, ?

Ans:1
The pattern adds alternate prime numbers to the previous term:

29 + 2 = 31

31 + 5 = 36

36 + 11 = 47

47 + 17 = 64

64 + 23 = 87

 

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13 thoughts on “Number Series”

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