In the following questions, two equations numbered I and II are given. You have to solve both the equations and Give Answer If
1.
x2 + 25x + 156 =0
y2+27y+182 =0
Ans:2 I. x2 + 25x + 156 =0X2 + 12x + 13x +156 =0
(x+12) (x+13) =0
x = -12, -13
II. y2+27y+182 =0
Y2 + 14y + 13y + 182 =0
(y+13) (y+14) =0
y =-13, -14
x ≥ y
2.
4x+2y =14
3x+6y =24
Ans:3 4x+2y =14 —– (1) 3x+6y =24 —– (2) Solve the equation, we get x = 2 and y =3
3.
x = ∛1728
y = √(√20736)
Ans:5 I. x = ∛1728 x=12 II. y = √(√20736) y= √144 y = 12 x=y
4.
(x2 – 122) =0
y = ∛2197
Ans:3 I. (x2 – 122) =0(x+12) (x-12) =0
x=12, -12
II. y = ∛2197
y =13
x < y
5.
4x+6y = 6
2x-3y =45
Ans:1 4x+6y = 6 —- (1) 2x-3y =45 —- (2) Solve the equations, we get x = 12 and y = -7 x> y
Directions:6-10) In the following questions, two equations numbered I and II are given. You have to solve both questions and give answer among the following options.
6.
4x²-4x-48=0
6y²-6y-12=0
Ans:5 I.4x²-4x-48=0 4x²-16x+12x-48=0 X=4,-3 II.6y²-6y-12=0 6y²+6y-12y-12=0 Y=2,-1 Thus relationship can’t be established