Directions:1-5) In each of the following questions, two equations (i) and (ii) are given. You have to solve them and find the correct option.

1.

i) 2x2-23x+56=0

ii) 3y2+13y+4=0

Ans:1
i) 2x2-23x+56=0

2x2-16x-7x+56=0

(2x-7)(x-8)=0

x= 7/2 or 8

ii) 3y2+13y+4=0

3y2+12y+y+4=0

(3y+1)(y+4)=0

y= -1/3 or -4

Hence x >y

2.

i) x2-22x+117=0

ii) 5y2+41y+42=0

Ans:1
i) x2-22x+117=0

x2-13x-9x+117=0

(x-13)(x-9)=0

x=13 or 9

ii) 5y2+41y+42=0

5y2+35y+6y+42=0

(y+7)(5y+6)=0

y=-7 or -6/5

Hence x >y

3.

i) 2x2-7x+5=0

ii) 2y2+y-28=0

Ans:5
i) 2x2-7x+5=0

2x2-2x-5x+5=0

(x-1)(2x-5)=0

x=1 or 5/2

ii) 2y2+y-28=0

2y2+8y-7y-28=0

(2y-7)(y+4)=0

y= -4 or 7/2

Hence the relationship cannot be determined.

4.

i) x4-[(9)9/2/√x]=0

ii) (4/√y)+ (5/√y)= √y

Ans:5
i) x4-[(9)9/2/√x]=0

x9/2-99/2=0

x9/2=99/2

x=9

ii) (4/√y)+ (5/√y)= √y

9/√y=√y

y=9

Hence, x= y

5.

i) x2+5x+4=0

ii) 3y2-13y+12=0

Ans:1
i) x2+5x+4=0

x2+4x+x+4=0

(x+1)(x+4)=0

x= -1 or -4

ii) 3y2-13y+12=0

3y2-9y-4y+12=0

(y-3)(3y-4)=0

y=4/3 or 3

Hence x< y

Directions:6-10) In the following questions, two equations numbered are given in variables p and q. You have to solve both the equations and find out the relationship between p and q. Then give answer accordingly.

6.

I. 3p2 – 17p + 10 = 0
II. 3q2 + 4q – 4 = 0

Ans:3
3p2 – 17p + 10 = 0

3p2 – 15p – 2p + 10 = 0

Gives p = 2/3, 5

3q2 + 4q – 4 = 0

3q2 + 6q – 2q – 4 = 0

Gives q = -2, 2/3

-2…. 2/3…… 5

p ≥ q

7.

I. 3p2 – 14p + 8 = 0
II. 3q2 – 20q + 12 = 0

Ans:5
3p2 – 14p +8 = 0

3p2 – 12p – 2p + 8 = 0

Gives p = 2/3, 4

3q2 – 20q + 12 = 0

3q2 – 18q – 2q + 12 = 0

Gives q = 6, 2/3

2/3….. 4….. 6

Relation cannot be determined.

8.

I. 3p2 – 19p + 28 = 0
II. 4q2 – 5q – 6 = 0

Ans:1
3p2 – 19p + 28 = 0

3p2 – 12p – 7p + 28 = 0

Gives p = 7/3, 4

4q2 – 5q – 6 = 0

4q2 – 8q + 3q – 6 = 0

Gives q = -3/4, 2

-3/4…… 2…… 7/3…. 4

p > q

9.

I. 6p2 + 23p + 21 = 0
II. 3q2 – 14q – 5 = 0

Ans:2
6p2 + 23p + 21 = 0

6p2 + 9p + 14p + 21 = 0

Gives p = -7/3, -3/2

3q2 – 14q – 5 = 0

3q2 – 15q + q – 5 = 0

Gives q = -1/3, 5

-7/3…… -3/2….. -1/3…… 5

p < q

10.

I. 2p2 – 7p + 3 = 0
II. 2q2 + 11q + 12 = 0

Ans:1
2p2 – 7p + 3 = 0

2p2 – 6p – p + 3 = 0

Gives p = 3, 1/2

2q2 + 11q + 12 = 0

2q2 + 8q + 3q + 12 = 0

Gives q = -3/2, -4

-4……. -3/2…… 1/2….. 3

p > q

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