Directions:1-5) In each of the following questions, two equations (i) and (ii) are given. Solve them and find the correct option.

1.
a) x4= 28561
b) [(y5/2)/√13] = [(2*4) +√25]2

Ans:3
a)x4= 28561x= 13 and -13

b) [(y5/2)/√13] = [(2*4)+√25]2
[(y5/2)/√13]= [8+5]2
y5/2= 131/2(13)2
y=13
Hence x ≤ y

2.
a)3x-2y=12
b)7x-6y=18

Ans:1
3x-2y=12………… (1)7x-6y=18………… (2)

Multiply (1) by 3 then we get,
9x-6y=36 ……………. (3)
After solving (2) and (3), we get, x=9 and y=7.5
Hence, x>y

3.
a)8x2-34x=- 8
b)23y2-368=0

Ans:5
a)8x2-34x=-88x2-34x+8=0
8x2-32x-2x+8=0
8x(x-4)-2(x-4) =0
x=4 and ¼

b)23y2-368=0
23y2=368
y2=16
y=4 and -4
Hence, the relationship cannot be determined.

4.
a)x2+12x+36=0
b)y2+7y+6=0

Ans:3
a)x2+12x+36=0x2+6x+6x+36=0
x(x+6)+6(x+6)=0
x=-6 and -6
b)y2+7y+6=0
y2 +y+6y+6=0
y(y+1)+6(y+1)=0
y=-1 and -6
Hence, x≤y

5.
a)√360 x + (200)1/2=0
b)√500 y + √402=0

Ans:1
a)√360 x + (200)1/2=0√360 x=-√200
x=-0.74
b)√500 y + √402=0
√500 y= -√402
y=-√402/√500
y=-0.89
Hence, x>y

Directions:6-10) In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer.

6.
I.2x2 – 15x+ 28 = 0
II.10y2 – y- 119 = 0

Ans:3
2x2 – 15x+ 28 = 0X = 4,7/2
10y2 – y- 119 = 0
Y = 7/2 ,-17/5
x ≥ y

7.
I.6x2 – 47x + 80 = 0
II.2y2 – 9y + 10 = 0

Ans:3
6x2 – 47x + 80 = 0X= 16/3 , 5/2
2y2 – 9y + 10 = 0
Y = 5/2, 4/2
X ≥ y

8.
I.20x2 – 51x + 27 = 0
II.15y2 – 16y + 4 = 0

Ans:1
20x2 – 51x + 27 = 0X = 9/5, 3/4
15y2 – 16y + 4 = 0
y= 2/5, 2/3
X>Y

9.
I.8x2 +10x -12 =0
II.7y2+25y+12=0

Ans:5
8x2 +10x -12 =0X= -16/8, 6/8
X= -2, 0.75
7y2+25y+12=0
Y = -21/7, -4/7
= -3,-4/7

If x = y or relation cannot be established.

10.
I.4x+7y =14.03
II.3X+17y = -4.87A

Ans:1
X=5.8; Y = -1.31

Pages: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30

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